Merit List 2013 by KPK Medical Colleges


All medical colleges located in Khyber Pakhtunkhwa are going to start the admission process. In response to their offer, huge number of students applied for admission in the medical colleges. After that, the medical colleges conducted the entry test in which about 19484 students appeared. For this purpose, three exams centers were set up, in which all these candidates were appeared. In Peshawar exams centers, about 13818 candidates appeared. In Swat exams center, 2935 candidates and in Abbottabad exams center about 2737 candidates were appeared. The result of the entry test of the students seeking admission in the medical colleges, will be announced within 36 hours.

When the result of entry test will be received, we will display the merit list of the successful candidates. The administration will provide all merit lists including 1st, 2nd and 3rd merit list of the candidates for grant of admission in the medical and dental colleges.

KMU 1st Merit Lists 2013 Announced Soon

KMU 2nd Merit Lists 2013 Announced Soon

KMU 3rd Merit Lists 2013 Announced Soon

KPK Medical Colleges List

  1. Khyber Medical College
  2. Ayub Medical College
  3. Khyber Girls Medical College
  4. Saidu Sharif Medical College
  5. Bacha Khan Medical College
  6. Gomal Medical College
  7. Bannu Medical College
  8. Khyber College of Dentistry
  9. Ayub Dental College
  10. KMU Institute of Medical Sciences

Merit Calculation Method:

Merit Calculation method is so easy of KPK Medical Colleges and the respective method is given here with an example:

SSC or Equivalent qualification = 10%

Adjusted HSc. marks or equivalent level marks= 40%

Entrance Test Marks = 50%


  • A student carry 76.5% in Matric, 79.1% in Inter (F.Sc) and 57.5% in the Entrance test of KMU then the merit will be calculated as
  • Weightage for SSC     =    76.5 x 0.1     =    7.65
  • Weight age for F.Sc     =    79.1 x 0.4     =    31.64
  • Weight age for Entrance Test     =    57.5 x 0.5     =    28.75
  • Merit score of the candidate    =     a+b+c = 7.65+31.64+28.75    =     68.04


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